Solving equation 58: 2x^2 β 9x^2; 5 β 3x + y + 6 is a fundamental skill in mathematics, and it can sometimes be challenging, especially when dealing with complex expressions. In this article, we will delve into the process of solving the equation 58: 2x^2 β 9x^2; 5 β 3x + y + 6, step by step. We will explore different methods and techniques that will help us simplify the equation and find the values of βxβ and βyβ that satisfy it. By the end of this article, you will have gained a solid understanding of solving equations and will be able to tackle similar problems with confidence.

** Understanding the Equation 58: 2x^2 β 9x^2; 5 β 3x + y + 6**

Before we proceed with the solution, letβs take a closer look at the given equation: 58: 2x^2 β 9x^2; 5 β 3x + y + 6. This equation contains three distinct terms: 2x^2, -9x^2, and 5 β 3x + y + 6. Our main objective is to determine the values of βxβ and βyβ that satisfy this equation and make it true.

**Combining Like Terms**

To simplify the equation, we begin by combining the like terms. In this case, we have two terms with x^2, namely 2x^2 and -9x^2. By combining these terms, we get -7x^2. The equation now becomes 58: -7x^2; 5 β 3x + y + 6.

**Isolating Variables**

**1. Isolating βxβ**

To proceed further with finding the values of βx,β we aim to isolate βxβ on one side of the equation. Letβs move all terms containing βxβ to the left side and constants to the right side:

-7x^2 = 58 β (5 + 6) + y

**2. Isolating βyβ**

Similarly, to determine the value of βy,β we need to isolate it on one side of the equation:

y = 58 β (5 + 6) β 7x^2

**Using the Quadratic Formula**

Since the equation contains a quadratic term (-7x^2), we can explore another method to find the solutions for βxβ using the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for βxβ are given by:

x = (-b Β± β(b^2 β 4ac)) / 2a

In our equation, a = -7, b = 0, and c = 58 β (5 + 6) + y. Substituting these values into the quadratic formula, we get:

x = (Β± β(0 β 4*(-7)*(58 β (5 + 6) + y))) / 2*(-7)

**Checking the Solutions**

After obtaining the values for βxβ using either method, it is essential to validate these solutions by substituting them back into the original equation. This step helps us confirm if both sides of the equation are equal, thereby verifying the accuracy of our solutions.

**Graphical Representation**

An alternative way to visualize the solutions is through graphical representation. We can plot the equation on a graph, and by finding the points where it intersects the x-axis, we can determine the solutions for βx.β Additionally, the graphical representation provides valuable insights into the behavior of the equation. (55. x ^ 2 β 3x + 2 58. 2x ^ 2 β 9x ^ 2)

**Conclusion**

Solving equations is a crucial skill that finds applications in various fields of mathematics and beyond. In this article, we successfully tackled the equation 58: 2x^2 β 9x^2; 5 β 3x + y + 6 using different methods, such as isolating variables and employing the quadratic formula. By understanding these techniques, you can confidently approach similar equations and arrive at accurate solutions.